Hi tom, I want day, month, minute and years difference everyting in seconds. SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is crossed once. ADD_MONTHS. I want to calculate the current Age from Date of Birth in my Oracle function. The following illustrates the syntax of the DATEPART. Recall that earlier I mentioned that in my example I. (date1 - date2)The TRUNC (date) function returns date with the time portion of the day truncated to the unit specified by the format model fmt. DP_MONTH returns the distance between the months capturing the input dates. hh is a two digits of hour (00 through 23). YEAR: Stores the year information only, either in 2-digit or 4-digit format. create table test_table ( customer_num NUMBER, card_number char(2), card_issue_date DATE, card_expire_date DATE ). 9. The MDX DateDiff function for Essbase returns the difference (a number) between two input dates in terms of the specified date-parts, following a standard Gregorian calendar. Example. Should I change (edit) the title or delete and re-post the question properly? This is what I'm addressing. And what date you want to get for example difference between dates 456 days it's mean: 1 year 3 month and several days. 7 Date and Time Functions. 25) AS `years`, COUNT(FLOOR(DATEDIFF(NOW(),`startdate`)/365. For ex. count the number of elapsed time, taking care of daylight savings: day+1 - day = 1 = 24h (but using midnight time and daylight savings it could be 0 day and 23h)DATEDIFF(): It finds the difference between two dates passed to it. DAYS function. Do this even for a single day—e. We learned how to get work orders that took longer, get the oldest employees, the time between the. Click on the function name to jump to a discussion of that function. My DOB- 02-feb-1984 so my age should get as 27 Years 2 months 8 days How to do it. For example, assume that you had two elements, FIRST_NAME and LAST_NAME to concatenate into a 30-character field. date_from, evnt. Second option is wrong when start hours/minutes/seconds is less then end. Previous SQL Server Functions Next . Try SELECT FORMAT (DATEADD (month, -1, GETDATE ()),'MM/yyyy'); It will give you previous month and the year. 一重引用符で囲んだ'YYYY-MM-DD[*HH:MI[:SS]]'形式の文字列(*はコロン(:)または空白でも可)、または現在の日付を返す引用符なしの@DATENOW. event_id, evnt. NEXT_QUARTERDECLARE @gapPeriod DATETIME = DATEADD(MONTH,-2,GETDATE()); --Period:Last 2 months. Viewed 417k times 57 I would. This expression: to_date(SYSDATE, 'yyyy-MM-dd') doesn't make sense. For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. The Days, Months, and Years parameters can be negative or positive. NEXT_DAY: Returns a datetime value that represents the first weekday, named by string-expression, that is later than the date inexpression. This is going to be short:. Syntax: TIMESTAMPADD (interval, expr, timestamp) Example:. 2. We would like to show you a description here but the site won’t allow us. Parameter Description; date1, date2: Required. join our newsletter and get access to exclusive content every month. Syntax. Beneath the plainness of its name, it hides a little depth. The format argument is a string format that specifies which unit the date should be rounded to. mysql> SELECT EXTRACT (DAY FROM "2021-10-24") AS SHOW_DAY; Here, we have written a SELECT query with the EXTRACT () function to get the day from the given date. *You may also use the DATEDIFF function. DATE_DIFF. 0 for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query . Improve this answer. SYSDATE) and subtracting a date from a timestamp (e. datediff isn't a function in Oracle. Share. PeopleTools uses the SQL directly from the view definition (view text) and doesn't generate anything, so no meta-SQL wrapping is done. I would recommend. Would give you rows where date2 (the later date) is 60 to 90 days later than date1. 5. 7 Reference Manual :: 12. date_open END. 1. The month and the last day of the month are defined by the parameter. DATEDIFF(MONTH, 0, GETDATE())-1, 0) AND DATEADD(MONTH, DATEDIFF(MONTH, -1, GETDATE())-1, -1) based on the comment below I have modified the query. Then Oracle will not use an index on the date_column and would need a separate function-based index on either TRUNC(date_column) or TO_CHAR(date_column, 'DD-MM-YYYY'). SELECT date_part ('month',age ('2016-06-30', '2018-06-30')) The result of this query is 0. Property)) STDEV(Property) EF Core 7. txt","path":"inst/csv/jarChecksum. Goal. however using the below sql statement im getting. 1. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. February 28 and March 31) can lead to unintuitive behavior; specifically, increasing the first date in the pair does not always increase the output value. SELECT --Start with total number of days including weekends (DATEDIFF (dd,@StartDate,@EndDate)+1) --Subtact 2 days for each full weekend (DATEDIFF (wk,@StartDate,@EndDate)*2) --If StartDate is a Sunday, Subtract 1 ELSE 0 END) --If EndDate is a Saturday, Subtract 1 FROM dual. Start date will. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. In addition, with DATEDIFF () the column is an argument to the function. Oracle 9i and later versions support CURRENT_DATE and CURRENT_TIMESTAMP. The DATEPART() function returns an integer which is a part of a date such as a day, month, and year. Move the start date to the next Monday, then add the calculated weeks. select (CURRENT_DATE - item_expired) as remaining_time from customers; While this will provide you with the remaining time,. then if day/month of dob is less than. . DATEADD (mm, 1, @Date) and subtract 1 day from it to get the last day of current month. If date1 is earlier than date2 , then the result is negative. select trunc ( (sysdate - to_date ('2012-02-28 15:20', 'YYYY-MM-DD hh24:mi')) / 24) from dual; You should have multiplied by. Just divide the total by 7 to get the weeks and then calculate the remaining days. Possible values: text representing an entry in the IANA time zone database. S is milliseconds in one or up to six digits. One truncates a date to the precision specified (kind of like rounding, in a way) and the other just returns a particular part of a datetime. I have to get the date from the system and calculate the date difference in days. Expressions can contain only one hint. ss is two digits of second (00 through 59). Select DATEDIFF (MM,0,GETDATE ()) Output - 1374, If getdate () output is "2014-07-23 19:33:46. Both integer (int) and big integer (bigint) are numeric data types used to store integer values. In PostgreSQL, you can take the difference in years, multiply by 12 and add. For example, you might use DateDiff to calculate the number of days between two dates, or the number of weeks between today and the end of the year. January 30, 2004 - 7:26 pm UTC. A) Get the difference in months of dates on the same day. In effect, substr (to_date ('01-02-2018','mm-dd-yyyy'),4,3) is the same as. The DATEDIFF() function returns the difference between two dates. In short. Where a. it returns the difference in days if datepart is day. 1. DATEADD () Adds or subtracts a specified time interval from a specified date. datepart: It is the part of the date like day, month, year, week, etc. Oracle Month to Date:Showing data 6 months greater than date parameter?? 607634 Mar 24 2010 — edited Mar 24 2010. DATE_ADD. SELECT TIMESTAMP_FORMAT (“2021-03-15”, “%Y”) as “Year of the date”; TO_DATE. Truncate a Date to a Specific Unit of Measure. 01/31/2021: Introduced in SQL Server 2012. The key is to use DATEADD and DATEDIFF along with the appropriate SQL timespan enumeration. Share. SYSTIMESTAMP). The result only contains the year, month and day, not the time. The syntax for DATEDIFF is pretty straightforward: DATEDIFF (datepart, startdate, enddate) Let’s explore the parameters used here: datepart: The unit of time you want to use for the calculation, like year, quarter, month, day, or even smaller units like hour, minute, or second. Month-difference between any given two dates: Have a look at the TIMESTAMPDIFF () function in MySQL. This command prints the order date in the specified format. Currently I am only returning 1. I recommend you have a stab yourself. ;-). If you are using MySQL there is the DATEDIFF function which calculate the days between two dates: SELECT dtCreated , bActive , dtLastPaymentAttempt , dtLastUpdated , dtLastVisit , DATEDIFF (dtLastUpdated, dtCreated) as Difference FROM Customers WHERE (bActive = 'true') AND (dtLastUpdated > CONVERT (DATETIME,. In PostgreSQL there are basically 2 functions to do the same, as we have both date_part and extract: SELECT current_date AS ACTUAL_DATE, EXTRACT (DAY FROM current_date) AS ACTUAL_DAY, EXTRACT (MONTH FROM current_date) AS ACTUAL_MONTH, EXTRACT (YEAR FROM current_date) AS ACTUAL_YEAR. Returns. Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011 DateDiff is not a function that exists in Oracle. Follow edited Apr 7, 2020 at. 2 -Increment by 1 into total months count -. For example the difference between 1st March 2011 and 3rd March 2012 is 1. Also, according to Oracle's documentation LAST_DAY returns a DATE. ReturnDate)) + ' days') ELSE CAST(DATEDIFF(day, Trips. columns c puts a limit on how many dates are returned. The date calculator calculates the difference between the 'Start Date' and 'End Date' and displays it in terms of the number of years, months, weeks and days between them. Here is an example that uses date functions. January 1 of any year defines the starting number for the week datepart, for example: DATEPART (wk, 'Jan 1, xxxx') = 1, where xxxx is any year. Get Number of Months Between 2 Dates. The part to return. We learned with examples, how to get information. Syntax. Each Standard calendar week is defined to start on Sunday and it spans 7 days. PostgreSQL. sql. DATE () Extract the date part of a date or datetime expression. Again, the expected results would be a value of 1. sql. They both do very different things. If date1 and date2 are either the same days of the month or both last days of months, then the. SELECT DATEADD(s,0,DATEADD(mm, DATEDIFF(m,0,getdate()),0))Time Calculator. To create the rows, use the month generation technique above. It means that the DATEPART function returns the number of times the boundary between two units is crossed. Oracle Fusion Application Toolkit Cloud Service - Version 11. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. It should have been DATEDIFF NOT DATEADD with respect to the WEEK parameter. Usage Notes¶. As GMB has mentioned in the comment above, date functions depend on the database type you are using. date. Last 3 Months. Also, according to Oracle's documentation LAST_DAY returns a DATE. I need to get the numbers of the months between two dates. Dates are always a joy to work with in any programming language, SQL not excluded. Improve this answer. The date functions are summarized in the table below. Enter a date format string that describes the Date2 parameter. 3 Answers. I wrote an SQL after reading through other questions. SELECT TO_DATE (“2021-01-15”) as “Date value”; TO_CHAR. g. I say ALL months as months can have 28 days (29 in a leap year), 30 days and 31 days which is why I wouldn't simply calculate the days between two dates. PostgreSQL - Date Difference in Months. In certain cases, such as string-based comparisons or when a result depends on a different timestamp format than is set in the session parameters, we recommend explicitly converting. Converting a raw number of days into a number of weeks and days is pretty simple. ( See. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. , SYSDATE - pr. The part can be the day of the date, month of the date, year of the date etc. Assuming that a. Dynamic views containing Date, Time, or DateTime fields must be wrapped with the appropriate meta-SQL. 2) format. Multiply it by seven to give the number of weeks spanned. 0. To calculate the number of days between date1 and date2, you can use either Day of. Oracle-compatible TO_CHAR function that can format a timestamp, a number. Based on the spreadsheet above, the following Excel function would return the following values:In Oracle, the datetime system function is SYSDATE. date1. oracle; datediff; or ask your own question. g. 1970年1月1日から2037年12月31日までの入力日付を示す数値。. DATE () Extract the date part of a date or datetime expression. JohnD JohnD. current_time() returns the date and time on the database client side. You may have to re-cast to a DATE datatype first. As shown clearly in the result, because 2016 is the leap year, the difference in days between two dates is 2×365 + 366 = 1096. ss is two digits of second (00 through 59). 5. select sysdate - date '2022-01-03' as delta from dual; The resulting value on the day I am running this is 37. 24. Functions. As we can see in the screen shot the query displays the months between the two dates. ReturnDate) AS nvarchar(max)) END) AS [Duration] As a side note: I used nvarchar(max) for consistency with the first part of your query. Here is the TSQL to calculate the last day of the current month. I have a question though. You should consider how many. AgeInYears value of 0 while in the other case the AgeInYears value is 1. Oracle Database enables you to perform arithmetic operations on dates and time stamps in several ways: Add a numeric value to or subtract it from a date, as in SYSDATE + 7; Oracle Database treats the number as the number of days. select datediff (q,'03-30-2005','04-01-2005') will return 1. ) that are available and in this tutorial, we look at how to use the DATEADD function in SQL queries, stored procedures, T-SQL scripts,. Subtracting two dates will return if and only if they are the same year, the same month, the same day, the same hour, the same minute, and the same second. Would give you rows where date2 (the later date) is 60 to 90 days later than date1. For example, suppose you have values below the start and end times. . February 28 and March 28) and when the days of the month are the last day of the month (e. So, it starts with RIGHT(“00”. Only 10+ years later - here's a db<>fiddle which demonstrates the difference between subtracting a date from a date (e. Month and day of the year don’t appear to be factored into the equation. g. CREATE TABLE [table] ( ID int IDENTITY(1,1) PRIMARY KEY, Title nvarchar(20), Date date, Amount money. TIMESTAMP or TIMESTAMPZ. 0. DATEDIFF(expr1,expr2) DATEDIFF() は、ある日付から別の日付までの日数の値として表現された expr1 − expr2 を返します。expr1 および expr2 は、日付または日付時間式です。 値の日付部分のみが計算に使用されます。One practical example of using the DATEDIFF function in SQL Server is in a WHERE clause by selecting all employees in the AdventureWorks2008R2 database whose date of hire was in March 2003. DATEDIFF Examples Using All Options. I need to calculate the difference between two dates in Oracle sql and show it in the following format: 'x years y months z days'. Another example using the MONTHS_BETWEEN function in Oracle/PLSQL is: MONTHS_BETWEEN (TO_DATE ('2003/07/01', 'yyyy/mm/dd'), TO_DATE ('2003/03/14', 'yyyy/mm/dd') ) would return 3. 1,984 1 1 gold badge 17 17 silver badges 31 31 bronze badges. 0. So in order to get specific type of delivery for the last 3 months I was thinking to get today's date and convert it to 01/mm/yyyy format and ref it with the delivery month in the table to get least 3 month including. SUBDATE (`Date`,WEEKDAY (`Date`)-1) This is the simplest version and returns the full date of the Sunday for the given week. CODE = 'CONTACT_CLIENT' THEN a. So if there are two dates separated by one day, the year difference can be 1 (see select datediff (year, '20141231', '20150101') ). g. Query all. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate. You can't transform this value to date by to_date function. Expressions that return a value of any of the following built-in data types: a date, a timestamp, a character string, or a graphic string. I've tried Datediff(day, start_date, end_date), but I was prompt with: invalid column name. The following example illustrates how to use the. TZD is a time zone designator ( Z, + / - hh: mm or + / - hhmm ). Month difference between two dates in sql server. 2. 2425): datediff (day, {start-date}, {end-date},) / 365. Sum (r => EF. For example, PERIODROLLING can compute sales for a period that starts at a quarter before and ends at a quarter after the current quarter. The int data type takes 4 bytes as storage size whereas. The add_days variable can be negative. ). This gets the year difference between the birth date and the current date. + (Concatenation) operator. If you want to confirm, simply run this. %DateDiff – returns the number of days between two date values. That is, this function returns the count (as a signed integer value) of the specified datepart boundaries crossed between the specified start date and end date. It takes into account the fact that DATEDIFF() computes the difference without considering what month or day it is (so the month diff between 8/31 and 9/1 is 1 month) and handles that with a case statement that decrements the result. declare @EmployeeStartDate datetime='01-Sep-2013' declare @EmployeeEndDate datetime='15-Nov-2013' select DateDiff (mm,@EmployeeStartDate, DateAdd (mm, 1,@EmployeeEndDate)) If. You can even find the number of hours, minutes, seconds, and so on in terms of details in between the two. e. Teams. Function. i need to find the difference of two dates as the number of months: find the last day of the month of both the dates. The easiest is the connect by level method: Copy code snippet. The Question asked for "6 months from the system date". But I suggest you add a computed column to the table: alter table Family add AgeYears as Year (getdate ()) - Year (dob) - 1 + case when Month (getdate ()) > month (dob) then 1 when month (getdate ()) < month (dob) then 0 else case when day (getdate ()) >= day (dob) then 1 else 0 end end. Syntax. (CASE WHEN Trips. For example, adding three months or 12 days to a starting date. Improve this answer. SELECT {sales} ON COLUMNS, Filter( [Time dimension]. MySQL DATEDIFF: Calculating weeks, months, or years between two dates. Date3(year, month, day) – similar to the ‘Date’ function described above, except that the three parameters are passed in as separate year, month and day values. DATEDIFF is built to return the number of date BOUNDARIES that are crossed. The Stored Procedure accepts two inputs - A start date and end date of the date range desired by the user. Field or Control. , year, quarter, month, day, hour, minute, second), startdate is the starting date or time, and enddate is the ending date or time. Share. The following example returns a difference in months between two dates: July 01 2017 and January 01 2017: SELECT MONTHS_BETWEEN( DATE '2017-07-01', DATE '2017-01-01') MONTH_DIFF FROM. @WernfriedDomscheit YYYY-MM-DD is not a date it is just a formatted string. Get the number of months between two dates. 2. - Find the “date_diff” in hours and multiply it by “60”. This requires breaking the date into its year, month, and day parts, putting them together in "yyyy/mm/dd" format, then casting that back to a date. Option 1. I apologize for the misinformation. Hi team i need to get the exact month differences between two dates i am using oracle sql for my project . Our SQL tutorial will teach you how to use SQL in: MySQL, SQL Server, MS Access, Oracle, Sybase, Informix, Postgres, and other database systems. SQL Server ignores that this is just one day. I am looking for solution how to select number of days between two dates without weekends and public holidays. (Query using SQL server 2005 and 2008 is allowed). If the resulting date would have more days than are available in the resulting month, the result is the last day of that month. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate Result: DiffDate 61 So, for example: WHERE date2 - date1 BETWEEN 60 AND 90. MONTHS_BETWEEN: Returns an estimate of the number of months between expression1 and expression2. Viewed 32k times. 16. DATEDIFF is a common function in the SQL Server to find the number of days between two dates. EOMONTH (date [,months to add) Returns the last do of the month with an optional parameter to add months (+ or -). As Spark doesn't provide the other unit, I use below method, select (bigint (to_timestamp (endDate))) - (bigint (to_timestamp (startDate))) as time_diff. Admission_Date < ADD_MONTHS (sysdate, -5) which could still use an index on that column, if there is one. 1. SELECT SYSDATE AS "Date" FROM DUAL; SYSDATE returns the system date and time but does not display the time unless formatted to do so with the function TO_CHAR (): SELECT TO_CHAR (SYSDATE,. There are several date functions (DATENAME, DATEPART, DATEADD, DATEDIFF, etc. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. datediff('MONTH', pr. – user330315. 8. This is so as for the ease of use later for php. Oracle's database does not have (nor need) a datediff() function. The two date fields are "timestamp" format (date and time). inner select select DATEDIFF(MONTH, 0, GETDATE()) will give the number of months from 1900-01-01 here it is 1350. DD is a two-digit day of the month (01 through 31). Was this tutorial helpful? Previously Oracle ROW_NUMBER Up Next Oracle ADD_MONTHS This tutorial provides you with the most commonly used Oracle date. 41935483870968. For example, on July 10th, this SQL returns a list of all dates from May 1 through July 10 - i. For both ADD_MONTHS and DATEADD, if the result month has fewer days than the original day, the result day of the month is the last day of the result month. This function adds a number (a signed integer) to a datepart of an input date, and returns a modified date/time value. You can even find the number of hours, minutes, seconds, and so on in terms of details in. Connect and share knowledge within a single location that is structured and easy to search. columns. Syntax. TIMESTAMPADD () manipulates data of the data types DATE and DATETIME based on a calendar year. ADD_MONTHS. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the. {"payload":{"allShortcutsEnabled":false,"fileTree":{"inst/csv":{"items":[{"name":"jarChecksum. Using this, I can find the first day of any given month using, but just that month and it does not take into consideration whether it is a business day or not. DateAdd. Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011So, for example: WHERE date2 - date1 BETWEEN 60 AND 90. This question was incorrectly asked. DATE_DIFF = 1. I know it exists in SQL Server. We need to subtract a second from first day of current month. Dateadd function is not working in oracle SQL. date_open are both of type date, you can simply subtract them to get a difference in days. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. g. Hot. date_to, DATEDIFF(DD, evnt. The name of the order date month is printed, followed by the day of the month, a comma, and four-digit year. The following shows the syntax of the DATEPART() function: DATEPART ( date_part , input_date ) Code language: SQL (Structured Query Language) (sql) The DATEPART() takes two arguments: date_part is the part of a date to be extracted. It helps me a lot . DATE_ADD () Add time values (intervals) to a date value. The math is 100% accurate for dates within a couple of hundred years or so. I am trying to come up with a way in Oracle to calculate the difference between dates in days. The %DateAdd meta-SQL function returns a date by adding add_days to date_from. This is in the manual. Return the months between dates Find the difference between datetimes in years down to seconds Define default formatting for datetime data types Cheat sheet. We would like to show you a description here but the site won’t allow us. e it takes the quarter in which the start date exists and subtracts it from the quarter in which the end date exists. Taking example 1, Oracle is telling me that 3rd Feb was a longer time ago than Informatica is telling me it is. The DATEADD() function adds or subtracts a specified time interval from a date. 1. Then the 1 represents the first day of that month. Add 18 years to the date in the BirthDate column, then return the date: SELECT LastName, BirthDate, DATEADD (year, 18, BirthDate) AS DateAdd FROM Employees; Try it Yourself ». This works because you have no issue with months and years or one-digit vs. 4k 4 4 gold badges 40 40 silver badges 53 53 bronze badges. 2258064516. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual;. 可以用以下方法在oracle中实现该函数的功能: 1. Hi tom, I want day, month, minute and years difference everyting in seconds. @Bruno - If the data types are TIMESTAMP WITH TIME ZONE, the interval that results from subtracting the two should take care of any time zone/ daylight savings time conversion. We’re calculating months of service in this example. COMPUTE days2 = DATEDIFF(date2,date1,"days"). If both inputs are unknown time zones, then the DateDiff will be calculated on both Dates as if they were defined in the same time zone. mysql> SELECT. I am trying to create a new column that will show the age of the person on the date that they took up the membership. Select between two months. select months_between(date '2015-03-19', date '2012-01-06') as month_diff from dual; MONTH_DIFF ----- 38. - Find the “date_diff” in hours and multiply it by “60”. You can use this to fetch all the days between two dates by: Subtracting the first date from the last to get the number of days. Example-3: List the name and surname of students whose age 17. object_id ) AS nbr FROM sys. February 28 and March 31), the fractional portion is zero, even if the days of the month are not the same. When the reporting date month is the same as the target month you can get a round up To get the number of month or day, you change the first argument to month or day as shown below: Notice that the DATEDIFF () function takes the leap year into account. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. If date1 and date2 are either the same days of the month or both last days of months, then the result is always an integer. The return type is always DATE, regardless of the datatype of date. Snowflake doesn't offer a function that does that. Examples of Results in Months. The function supports units of years, quarters, months, weeks, days, hours, minutes, seconds, milliseconds, microseconds, and nanoseconds.